Question

what number has 9 ten thousands, 8 fewer thousands than ten thousands, 2 fewer hundreds than ten thousands, no tens, and 5 fewer ones than hundreds?

Explanation:

Step1: Determine the ten - thousands place

The number has 9 ten - thousands. So the digit in the ten - thousands place is 9.

Step2: Determine the thousands place

We know that the number of thousands is 8 fewer than ten - thousands. Since the ten - thousands digit is 9, the thousands digit is $9 - 8=1$.

Step3: Determine the hundreds place

The number of hundreds is 2 fewer than ten - thousands. Since the ten - thousands digit is 9, the hundreds digit is $9 - 2 = 7$.

Step4: Determine the tens place

The problem states that there are no tens. So the digit in the tens place is 0.

Step5: Determine the ones place

The number of ones is 5 fewer than hundreds. Since the hundreds digit is 7, the ones digit is $7-5 = 2$.

Now, we combine the digits from the ten - thousands, thousands, hundreds, tens, and ones places. The number is composed as follows: ten - thousands place: 9, thousands place: 1, hundreds place: 7, tens place: 0, ones place: 2. So the number is 91702.

Answer:

91702