Question

1. what pressure is required to compress 196.0 liters of air at 1.00 atm into a cylinder whose volume is 26.0 liters?

Explanation:

Step1: Aplicar ley de Boyle

$P_1V_1 = P_2V_2$

Step2: Identificar valores iniciales

$P_1 = 1.00\ atm$, $V_1 = 196.0\ L$

Step3: Identificar valor final de volumen

$V_2 = 26.0\ L$

Step4: Despejar $P_2$

$P_2=\frac{P_1V_1}{V_2}$

Step5: Sustituir valores

$P_2=\frac{1.00\ atm\times196.0\ L}{26.0\ L}$
$P_2 = 7.54\ atm$

Answer:

$7.54\ atm$