Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

c. what is the probability that an offspring will be short and have pur…

Question

c. what is the probability that an offspring will be short and have purple flowers? practice: now try this complete problem: cross a short plant that is heterozygous for flower color with a plant that is heterozygous for height and has white flowers. 1. what is the probability of an offspring being tall with purple flowers? 2. what is the probability of an offspring being tall with white flowers? 3. what is the probability of an offspring being short with purple flowers? 4. what is the probability of an offspring being short with white flowers?

Explanation:

Step1: Determine the genotypes of the parents

Let \(T\) represent the allele for tall height and \(t\) for short height, \(C\) for purple - flower color and \(c\) for white - flower color. The first parent is short and heterozygous for flower color, so its genotype is \(ttCc\). The second parent is heterozygous for height and has white flowers, so its genotype is \(Ttcc\).

Step2: Determine the gametes produced by each parent

The \(ttCc\) parent can produce \(tC\) and \(tc\) gametes. The \(Ttcc\) parent can produce \(Tc\) and \(tc\) gametes.

Step3: Create a Punnett - square

\(tC\)\(tc\)
\(tc\)\(ttCc\)\(ttcc\)

There are a total of 4 possible genotypes in the offspring.

Step4: Calculate probabilities for each question

1. Probability of an offspring being tall with purple flowers (\(TtCc\))

There is 1 \(TtCc\) out of 4 possible genotypes. So the probability is \(\frac{1}{4}\).

2. Probability of an offspring being tall with white flowers (\(Ttcc\))

There is 1 \(Ttcc\) out of 4 possible genotypes. So the probability is \(\frac{1}{4}\).

3. Probability of an offspring being short with purple flowers (\(ttCc\))

There is 1 \(ttCc\) out of 4 possible genotypes. So the probability is \(\frac{1}{4}\).

4. Probability of an offspring being short with white flowers (\(ttcc\))

There is 1 \(ttcc\) out of 4 possible genotypes. So the probability is \(\frac{1}{4}\).

Answer:

  1. \(\frac{1}{4}\)
  2. \(\frac{1}{4}\)
  3. \(\frac{1}{4}\)
  4. \(\frac{1}{4}\)