Question

1. what would be the product of ((3x + 0.5)(3x - 0.5))?

a. (9x^2 - 1.5)

b. (9x^2 + 0.25)

c. (9x^2 + 0.75)

d. (9x^2 - 0.25)

Explanation:

Step1: Recognize difference of squares

This is $(a+b)(a-b)=a^2-b^2$

Step2: Define $a$ and $b$

Let $a=3x$, $b=0.5$

Step3: Calculate $a^2$

$a^2=(3x)^2=9x^2$

Step4: Calculate $b^2$

$b^2=(0.5)^2=0.25$

Step5: Substitute into formula

$(3x+0.5)(3x-0.5)=9x^2 - 0.25$

Answer:

d. $9x^{2} - 0.25$