Question

what is the resistance of a light bulb if a potential difference of 120 v will produce a current of 0.5 a in the bulb?
0.0042 ω
0.5 ω
60 ω
240 ω

Explanation:

Step1: Recall Ohm's law

$V = IR$, where $V$ is potential difference, $I$ is current and $R$ is resistance. We need to solve for $R$.

Step2: Rearrange the formula for $R$

$R=\frac{V}{I}$

Step3: Substitute given values

Given $V = 120$ V and $I=0.5$ A, so $R=\frac{120}{0.5}=240$ $\Omega$

Answer:

240 $\Omega$ (corresponding to the last option)