Question

what are the solutions for \\(\frac{1}{2}x + 8 \leq 10\\)?

Explanation:

Step1: Subtract 8 from both sides

To isolate the term with \( x \), we subtract 8 from both sides of the inequality \(\frac{1}{2}x + 8 \leq 10\). This gives us \(\frac{1}{2}x + 8 - 8 \leq 10 - 8\), which simplifies to \(\frac{1}{2}x \leq 2\).

Step2: Multiply both sides by 2

To solve for \( x \), we multiply both sides of the inequality \(\frac{1}{2}x \leq 2\) by 2. This gives us \( 2\times\frac{1}{2}x \leq 2\times2\), which simplifies to \( x \leq 4 \).

Answer:

\( x \leq 4 \)