Question

what are the solutions to the equation $0 = x^2 - x -6$? select two options
$x = -3$
$x = -2$
$x = 0$
$x = 2$
$x = 3$

Explanation:

Step1: Factor the quadratic equation

We need two numbers that multiply to $-6$ and add to $-1$. These numbers are $-3$ and $2$.
$x^2 - x - 6 = (x - 3)(x + 2)$

Step2: Set factors equal to 0

Set each factor to 0 to solve for $x$.
$x - 3 = 0$ or $x + 2 = 0$

Step3: Solve for x in each equation

For $x - 3 = 0$, add 3 to both sides: $x = 3$.
For $x + 2 = 0$, subtract 2 from both sides: $x = -2$.

Answer:

B. $x=-2$, E. $x=3$