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what type of number is $52i + 7.5$? choose all answers that apply: a re…

Question

what type of number is $52i + 7.5$? choose all answers that apply: a real b imaginary c complex

Explanation:

Brief Explanations
  1. Recall the definitions:
  • A real number is a number that can be represented on the number line and does not involve the imaginary unit \(i\). The number \(52i + 7.5\) has a term with \(i\), so it is not a real number (so option A is incorrect).
  • An imaginary number is a number of the form \(bi\) where \(b\) is a non - zero real number. The number \(52i+7.5\) has a real part (\(7.5\)) and an imaginary part (\(52i\)), so it is not a pure imaginary number (so option B is incorrect in the sense of pure imaginary, but we will see about complex).
  • A complex number is a number of the form \(a + bi\), where \(a\) and \(b\) are real numbers and \(i=\sqrt{- 1}\). In the number \(52i + 7.5\), we can rewrite it as \(7.5+52i\), where \(a = 7.5\) (real part) and \(b = 52\) (coefficient of the imaginary part). Also, all real numbers and all imaginary numbers are subsets of complex numbers. Since \(52i+7.5\) is in the form \(a + bi\) with \(a = 7.5\) and \(b = 52\), it is a complex number. Also, since it has an imaginary part (\(52i\)) and a real part (\(7.5\)), and the set of complex numbers includes numbers with both real and imaginary parts (or just real or just imaginary), we can also note that it is a complex number. Also, the term "imaginary" in the option - if we consider that any number with an \(i\) component is related to imaginary numbers, and complex numbers include imaginary numbers. But more precisely, the form \(a + bi\) is complex. And since \(52i+7.5\) has an imaginary part, it is a complex number. Also, the number has an imaginary component, so it is associated with imaginary numbers (the \(52i\) part) and is a complex number.
  • Wait, let's re - check:
  • Real numbers: Numbers like \(7.5\) are real, but when we add \(52i\) (an imaginary number), the whole number \(7.5 + 52i\) is not a real number (because real numbers have no imaginary part).
  • Imaginary numbers: Pure imaginary numbers are of the form \(bi\) (\(b

eq0\)). The number \(7.5+52i\) has a real part, so it is not a pure imaginary number. But sometimes the term "imaginary" is used in the context of complex numbers (since complex numbers include imaginary components). However, the option B says "Imaginary". The number \(52i+7.5\) has an imaginary part (\(52i\)), so in the sense that it contains an imaginary component, and since complex numbers are of the form \(a + bi\), and all numbers of the form \(a+bi\) are complex. Also, every imaginary number is a complex number (when \(a = 0\)) and every real number is a complex number (when \(b = 0\)). So \(7.5+52i\) is a complex number. Also, since it has an imaginary part, it is a complex number and we can also say it is related to imaginary numbers (because it has the \(i\) term). So the correct options are B and C? Wait, no:

  • Let's re - define:
  • Real number: A number that can be expressed without the imaginary unit \(i\). So \(7.5\) is real, but \(7.5 + 52i\) is not real (so A is out).
  • Imaginary number: A number of the form \(bi\), where \(b\in\mathbb{R}\) and \(b

eq0\). The number \(52i\) is imaginary. The number \(7.5+52i\) is a complex number that has an imaginary part. The set of imaginary numbers is a subset of complex numbers. So the number \(7.5 + 52i\) is a complex number, and since it contains an imaginary part (\(52i\)), we can say it is an imaginary - related complex number. But the option B is "Imaginary". Is \(7.5+52i\) an imaginary number? A pure imaginary number is \(bi\), but a complex number with a non - zero real and non - zero imaginary part is still a c…

Answer:

B. Imaginary, C. Complex