QUESTION IMAGE
Question
what variable represents the horizontal difference between two points in the distance formula?
a. z
b. δy
c. δx
d. h
which component of the distance formula represents the vertical difference between two points?
a. δa
b. δs
c. δz
d. δy
in logistics, the distance formula is used to optimize:
a. delivery routes
b. warehouse temperatures
c. vehicle load capacities
d. package sizes
what is the primary role of the distance formula in computer graphics?
a. sound engineering
b. text formatting
c. color rendering
d. object positioning
calculate the distance between the points (1, 2) and (4, 6)
a. 2 units
b. 3 units
c. 4 units
d. 5 units
the distance between (10, 15) and (2, 9) is:
a. 10 units
b. 9 units
c. 11 units
d. 12 units
which pair of coordinates would have the longest distance between them based on the distance formula?
Step1: Recall distance - formula concepts
The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\), where \(\Delta x=x_2 - x_1\) represents the horizontal difference and \(\Delta y=y_2 - y_1\) represents the vertical difference.
Step2: Answer the first question
The variable that represents the horizontal difference between two points in the distance formula is \(\Delta x\). So the answer to the first question is c. \(\Delta x\).
Step3: Answer the second question
The component of the distance formula that represents the vertical difference between two points is \(\Delta y\). So the answer to the second question is d. \(\Delta y\).
Step4: Consider logistics application
In logistics, the distance formula is used to optimize delivery - routes. So the answer to the third question is a. Delivery routes.
Step5: Think about computer - graphics application
In computer graphics, the primary role of the distance formula is in object positioning. So the answer to the fourth question is d. Object positioning.
Step6: Calculate distance for points \((1,2)\) and \((4,6)\)
Use the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\), where \(x_1 = 1,y_1 = 2,x_2 = 4,y_2 = 6\). Then \(d=\sqrt{(4 - 1)^2+(6 - 2)^2}=\sqrt{3^2+4^2}=\sqrt{9 + 16}=\sqrt{25}=5\). So the answer to the fifth question is d. 5 units.
Step7: Calculate distance for points \((10,15)\) and \((2,9)\)
Use the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\), where \(x_1 = 10,y_1 = 15,x_2 = 2,y_2 = 9\). Then \(d=\sqrt{(2 - 10)^2+(9 - 15)^2}=\sqrt{(-8)^2+(-6)^2}=\sqrt{64 + 36}=\sqrt{100}=10\). So the answer to the sixth question is a. 10 units.
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- c. \(\Delta x\)
- d. \(\Delta y\)
- a. Delivery routes
- d. Object positioning
- d. 5 units
- a. 10 units