Question

1. what will be the variation in the mean temperature (°f) if the outlier is included? 108, 107, 100, 120, 63, 119, 118

Explanation:

Step1: Calculate mean without outlier

First, identify 63 as the outlier. Calculate the mean of the non - outlier values: $(108 + 107+100 + 120+119+118)\div6=\frac{108 + 107+100 + 120+119+118}{6}=\frac{672}{6}=112$.

Step2: Calculate mean with outlier

Calculate the mean of all values: $(108 + 107+100 + 120+63+119+118)\div7=\frac{108 + 107+100 + 120+63+119+118}{7}=\frac{735}{7}=105$.

Step3: Find the variation

Subtract the mean with outlier from the mean without outlier: $112 - 105 = 7$.

Answer:

7