Question

what is the vertex of (h(x)=7(x + 5)^{2}+4?
(7, - 4)
(-4,5)
(5,4)
(-5,4))

Explanation:

Step1: Recall vertex - form of a parabola

The vertex - form of a parabola is $y = a(x - h)^2+k$, where the vertex is the point $(h,k)$.
For the function $h(x)=7(x + 5)^2+4$, we can rewrite it as $h(x)=7(x-(- 5))^2 + 4$.

Step2: Identify the vertex coordinates

Comparing $h(x)=7(x-(-5))^2 + 4$ with $y=a(x - h)^2+k$, we have $h=-5$ and $k = 4$. So the vertex of the function $h(x)$ is the point $(-5,4)$.

Answer:

(-5,4)