Question

what is the vertex of the graph of the function (f(x)=2(x - 4)^{2}-1)?

Explanation:

Step1: Recall vertex - form of a parabola

The vertex - form of a parabola is $y = a(x - h)^2 + k$, where $(h,k)$ is the vertex of the parabola.

Step2: Identify $h$ and $k$ values

For the function $f(x)=2(x - 4)^2-1$, comparing it with $y = a(x - h)^2 + k$, we have $h = 4$ and $k=-1$.

Answer:

$(4,-1)$