Question

when a rock tied to a string whirled in a horizontal circle somehow doubles in mass but keeps the same speed, the string tension view available hint(s) doubles remains the same decreases increases by four submit

Explanation:

Step1: Recall centripetal - force formula

The centripetal force $F_c$ acting on an object moving in a horizontal circular path is given by $F_c = \frac{mv^{2}}{r}$, where $m$ is the mass of the object, $v$ is the speed, and $r$ is the radius of the circular path. The tension in the string provides the centripetal force, so $T = \frac{mv^{2}}{r}$.

Step2: Analyze the effect of mass change

Let the initial mass be $m_1$ and the final mass be $m_2 = 2m_1$, with $v$ and $r$ remaining constant. The initial tension $T_1=\frac{m_1v^{2}}{r}$, and the final tension $T_2=\frac{m_2v^{2}}{r}=\frac{2m_1v^{2}}{r}=2T_1$.

Answer:

doubles