Question

which equation could be used to solve for the length of xy?
xy = (22)sin(41°)
xy = (22)cos(41°)
xy = \frac{22}{cos(41°)}
xy = \frac{22}{sin(41°)}

Explanation:

Step1: Recall sine - cosine definitions

In right - triangle XYZ, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$, $\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}$. Here, $\sin(41^{\circ})=\frac{XZ}{XY}$, and $XZ = 22$.

Step2: Solve for XY

$XY=\frac{22}{\sin(41^{\circ})}$

Answer:

$XY=\frac{22}{\sin(41^{\circ})}$