Question

which expression is equivalent to \\(\frac{4t^2}{3} \div \frac{1}{4t}\\)? \\(\frac{16t^3}{3}\\) \\(\frac{t}{3}\\) \\(\frac{3}{16t^3}\\) \\(\frac{3}{t}\\)

Explanation:

Step1: Rewrite division as multiplication

$\frac{4f^2}{3} \div \frac{1}{4f} = \frac{4f^2}{3} \times 4f$

Step2: Multiply numerators and denominators

$\frac{4f^2 \times 4f}{3} = \frac{16f^{2+1}}{3}$

Step3: Simplify the exponent

$\frac{16f^3}{3}$

Answer:

$\frac{16f^3}{3}$ (Option 1)