Question

which of the following equations is \\(\log_{9}(-x - 9) = -2\\) rewritten in exponential form? (1 point) \\(9^{-2} = -x - 9\\) \\(-9^{2} = -x - 9\\) \\(9^{-x - 9} = -2\\) \\(9 \cdot -2 = -x - 9\\)

Explanation:

Step1: Recall the logarithm definition

The logarithmic equation \(\log_b(a) = c\) can be rewritten in exponential form as \(b^c = a\). Here, \(b = 9\), \(a=-x - 9\), and \(c=-2\).

Step2: Apply the definition

Substitute the values of \(b\), \(a\), and \(c\) into the exponential form formula. So we get \(9^{-2}=-x - 9\).

Answer:

A. \(9^{-2}=-x - 9\)