Question

which is a quadratic function having a leading coefficient of 3 and a constant term of -12? $f(x)=3x^2 + 11x - 12$ $f(x)=-12x^2 + 3x + 1$ $f(x)=12x^2 + 3x + 3$ $f(x)=3x - 12$

Explanation:

Step1: Recall quadratic function form

A quadratic function has the form $f(x)=ax^2+bx+c$, where $a$ (leading coefficient) $
eq0$, and $c$ is the constant term.

Step2: Match required coefficients

We need $a=3$ and $c=-12$. Check each option:

• $f(x)=3x^2+11x-12$: $a=3$, $c=-12$
• $f(x)=-12x^2+3x+1$: $a=-12$, $c=1$ (does not match)
• $f(x)=12x^2+3x+3$: $a=12$, $c=3$ (does not match)
• $f(x)=3x-12$: This is linear, not quadratic (does not match)

Answer:

$f(x)=3x^2+11x-12$