Question

1. which segment is the hypotenuse? 7. which segment is opposite to ∠b? 8. solve for x. round to the nearest tenth, if necessary. 9. solve for x. round to the nearest tenth, if necessary. 10. solve for x. round to the nearest tenth of a degree, if necessary. copyright deltamath

Explanation:

6.

Step1: Recall hypotenuse definition

In a right - triangle, the hypotenuse is the side opposite the right - angle. In right - triangle $\triangle OQJ$ with right - angle at $Q$, the side opposite $\angle Q$ is $\overline{OJ}$.

Step1: Identify opposite side to an angle

In a triangle, the side opposite an angle is the side that does not form the angle. In $\triangle ABW$ with right - angle at $W$, the side opposite $\angle B$ is $\overline{AW}$.

Step1: Use cosine function

We know that $\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}$. Given $\theta = 18^{\circ}$ and hypotenuse $= 52$, and adjacent side $=x$. So $\cos18^{\circ}=\frac{x}{52}$.

Step2: Solve for $x$

$x = 52\times\cos18^{\circ}\approx52\times0.9511\approx49.5$

Answer:

B. $\overline{OJ}$

7.