Question

which are solutions of the equation $x^2 - 16 = 0$? check all that apply. $x = -8$ $x = -4$ $x = -2$ $x = 2$ $x = 4$ $x = 8$

Explanation:

Step1: Solve the equation \(x^2 - 16 = 0\)

We can rewrite the equation as \(x^2=16\).

Step2: Find the square roots of 16

The square root of a number \(a\) is a value \(x\) such that \(x^2 = a\). For \(a = 16\), we have \(x=\pm\sqrt{16}\). Since \(\sqrt{16}=4\), then \(x = 4\) or \(x=- 4\).

Answer:

B. \(x = - 4\), E. \(x = 4\)