Question

1. the width of a rectangle varies inversely with its length. if the width is 4 when the length is 12, find the width when the length is 16. (4,12)(x,16)

Explanation:

Step1: Find the constant of variation

Since width $w$ varies inversely with length $l$, we have $w\times l = k$ (constant). When $w = 4$ and $l=12$, then $k=4\times12 = 48$.

Step2: Find the new width

We know $k = 48$ and $l = 16$. Using $w\times l=k$, we can solve for $w$. So $w=\frac{k}{l}=\frac{48}{16}=3$.

Answer:

3