Question

wr = 6. find the missing segment lengths.
tu =
rv =
tr =
vw =
vu =
ts =
(2y + 40)° (6y + 28)°
2y + 40 = 6y+28
-4y=-12
y = 3

1. what type of triangle center is point a?
2. which point of concurrency is shown below?
3. point m is a centroid. solve for x.
4. sketch △jkl with centroid r. make sure to shown all congruency and angle markings.

Explanation:

Step1: Recall centroid property

The centroid divides each median in a 2:1 ratio. If \(M\) is the centroid and the segments of the median are \((3x + 18)\) and \((5x-22)\), then \(5x-22 = 2(3x + 18)\).

Step2: Expand the right - hand side

\[5x-22=6x + 36\]

Step3: Solve for \(x\)

Subtract \(5x\) from both sides: \(-22=x + 36\). Then subtract 36 from both sides to get \(x=-58\).

Answer:

\(x=-58\)