QUESTION IMAGE
Question
- write the definition of distance, acceleration, and velocity
2a circle: true or false: speed and velocity are the exact same thing.
2b explain your answer:
- calculate the speed of a car that travels 250 meters in 8 seconds?
b = 250 s +\frac{250}{8}=31.25
- calculate a cars speed that takes 1.2s to travel 5100m?
b = 1.2 s +\frac{b}{t}
t = 5100
put the correct letter on the line to match the definition with the word.
- position a
a. where an object is located
- speed b
b. how fast an object travels
- velocity d
c. change in velocity
- acceleration c
d. how fast an object is moving and direction
fill in the blanks with the correct term based on the column heading questions.
| description of motion | is the speed constant or changing? | is the velocity constant or changing? | is the object accelerating or not? |
|a sprinter is slowing down from 15m/s to 10m/s|
|a race car starts from rest and increases speed on a curved track|
|a bicycle rider moves at a steady rate|
Step1: Define distance, acceleration and velocity
Distance is the total length of the path traveled by an object. Acceleration is the rate of change of velocity of an object with respect to time. Velocity is the rate of change of the position of an object, which is a vector quantity (has both magnitude and direction).
Step2: Answer 2a and 2b
2a: False. 2b: Speed is a scalar quantity that only refers to how fast an object is moving. Velocity is a vector quantity that refers to the rate at which an object changes its position, which includes both the speed of the object and the direction of its motion.
Step3: Calculate speed for question 3
The formula for speed is $s=\frac{d}{t}$, where $d$ is distance and $t$ is time. Given $d = 250$m and $t=8$s, then $s=\frac{250}{8}=31.25$m/s.
Step4: Calculate speed for question 5
Using the formula $s = \frac{d}{t}$, with $d = 5100$m and $t = 1.2$s, we have $s=\frac{5100}{1.2}=4250$m/s.
Step5: Fill - in - the - blanks for motion description
- For the sprinter slowing down from 15m/s to 10m/s: The speed is changing (decreasing), the velocity is changing (since speed is changing and velocity includes speed and direction, here assume straight - line motion, so direction may be the same but magnitude of velocity is changing), and the object is accelerating (negative acceleration as it is slowing down).
- For the race car starting from rest and increasing speed on a curved track: The speed is changing (increasing), the velocity is changing (because both speed is increasing and direction is changing on a curved track), and the object is accelerating.
- For the bicycle rider moving at a steady rate: The speed is constant, the velocity is constant (assuming straight - line motion, if not, direction change would make velocity non - constant), and the object is not accelerating.
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- Distance: The total length of the path traveled by an object. Acceleration: The rate of change of velocity of an object with respect to time. Velocity: The rate of change of the position of an object, a vector quantity (magnitude and direction).
2a. False
2b. Speed is a scalar, velocity is a vector including direction.
- 31.25m/s
- 4250m/s
- A
- b
- d
- c
| Description of Motion | Is the speed constant or changing? | Is the velocity constant or changing? | Is the object accelerating or not? |
|---|---|---|---|
| A race car starts from rest and increases speed on a curved track | Changing | Changing | Accelerating |
| A bicycle rider moves at a steady rate | Constant | Constant (assuming straight - line) | Not accelerating |