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write the equation of the line parallel to the given line and passing t…

Question

write the equation of the line parallel to the given line and passing through the given point. 2x - 3y = 6, (-1, 4) answer

Explanation:

Step1: Convert to slope-intercept form

Rearrange $2x - 3y = 6$ to solve for $y$:
$-3y = -2x + 6$
$y = \frac{2}{3}x - 2$

Step2: Identify parallel line slope

Parallel lines have equal slopes, so $m = \frac{2}{3}$.

Step3: Use point-slope form

Substitute $m = \frac{2}{3}$ and point $(-1, 4)$ into $y - y_1 = m(x - x_1)$:
$y - 4 = \frac{2}{3}(x - (-1))$

Step4: Simplify to standard form

Expand and rearrange the equation:
$y - 4 = \frac{2}{3}(x + 1)$
$3(y - 4) = 2(x + 1)$
$3y - 12 = 2x + 2$
$2x - 3y = -14$

Answer:

$2x - 3y = -14$