Question

write an expression that is equivalent to $-4 + \frac{5}{8}y + 7 + \left(-\frac{2}{8}y\
ight)$. combine like terms to simplify. $-4 + \frac{5}{8}y + 7 + \left(-\frac{2}{8}y\
ight) = (-4 + 7) + \left\frac{5}{8}y + \left(-\frac{2}{8}y\
ight)\
ight = \square +?y$

Explanation:

Step1: Combine constant terms

First, we combine the constant terms \(-4\) and \(7\). The operation is \(-4 + 7\), which equals \(3\).

Step2: Combine \(y\)-terms

Next, we combine the terms with \(y\), which are \(\frac{5}{8}y\) and \(-\frac{2}{8}y\). Using the rule for combining like terms with fractions, we have \(\frac{5}{8}y-\frac{2}{8}y=\frac{5 - 2}{8}y=\frac{3}{8}y\).

Answer:

\(3+\frac{3}{8}y\)