Question

write the expression as a single power of 7.\\(\frac{7^8}{7^2}=\\)?\\(7^4\\)\\(7^6\\)\\(7^{10}\\)\\(7^{16}\\)

Explanation:

Step1: Apply exponent division rule

When dividing exponents with the same base, subtract the denominator exponent from the numerator exponent: $\frac{a^m}{a^n}=a^{m-n}$
For $\frac{7^6}{7^2}$, this gives $7^{6-2}$

Step2: Calculate the exponent

$6-2=4$, so the expression simplifies to $7^4$

Answer:

$7^4$