Question

y = -x²
plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. then click on the graph - a - function button.

Explanation:

Step1: Find the vertex

For $y=-x^2$, the vertex form is $y=a(x-h)^2+k$ where $(h,k)$ is the vertex. Here $h=0, k=0$, so vertex is $(0,0)$.

Step2: Find left points (x<0)

Choose $x=-1$: $y=-(-1)^2=-1$, point $(-1,-1)$
Choose $x=-2$: $y=-(-2)^2=-4$, point $(-2,-4)$

Step3: Find right points (x>0)

Choose $x=1$: $y=-(1)^2=-1$, point $(1,-1)$
Choose $x=2$: $y=-(2)^2=-4$, point $(2,-4)$

Answer:

The five points are:
Vertex: $(0,0)$
Left points: $(-1,-1)$, $(-2,-4)$
Right points: $(1,-1)$, $(2,-4)$