Question

xth grade > jj.6 calculate mean absolute deviation juv
a zookeeper recorded the lengths of 5 snakes in the zoo:
19 centimeters 94 centimeters 52 centimeters 94 centimeters 14 centimeters
what was the mean absolute deviation of the snake lengths?
if the answer is a decimal, round it to the nearest tenth.
mean absolute deviation (mad): ________ centimeters
submit

Explanation:

Step1: Calculate the mean length

$$\text{Mean} = \frac{19 + 94 + 52 + 94 + 14}{5} = \frac{273}{5} = 54.6$$

Step2: Find absolute deviations

$|19 - 54.6| = 35.6$, $|94 - 54.6| = 39.4$, $|52 - 54.6| = 2.6$, $|94 - 54.6| = 39.4$, $|14 - 54.6| = 40.6$

Step3: Calculate MAD of deviations

$$\text{MAD} = \frac{35.6 + 39.4 + 2.6 + 39.4 + 40.6}{5} = \frac{157.6}{5} = 31.52$$

Step4: Round to nearest tenth

$31.52 \approx 31.5$

Answer:

31.5 centimeters