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Question
- you drop a ball off the roof of a hotel. it takes the ball 19 seconds to reach the ground.
a. how tall is the hotel?
b. what was the balls final velocity just as it reached the ground?
- you jump in the air and reach a max height of 6m. if you jump with a velocity of 1.8m/s, how long are you in the air for?
Problem 8a:
Step1: Select free-fall displacement formula
Use $h = \frac{1}{2}gt^2$, where $g=9.8\,\text{m/s}^2$, $t=19\,\text{s}$
Step2: Substitute values and calculate
$h = \frac{1}{2} \times 9.8 \times 19^2 = 4.9 \times 361$
Problem 8b:
Step1: Select free-fall velocity formula
Use $v = gt$, where $g=9.8\,\text{m/s}^2$, $t=19\,\text{s}$
Step2: Substitute values and calculate
$v = 9.8 \times 19$
Problem 9:
Step1: Time to reach max height
Use $t_1 = \frac{v_0}{g}$, where $v_0=1.8\,\text{m/s}$, $g=9.8\,\text{m/s}^2$
$t_1 = \frac{1.8}{9.8}$
Step2: Time to fall from max height
Use $t_2 = \sqrt{\frac{2h}{g}}$, where $h=6\,\text{m}$, $g=9.8\,\text{m/s}^2$
$t_2 = \sqrt{\frac{2 \times 6}{9.8}} = \sqrt{\frac{12}{9.8}}$
Step3: Total air time
$t_{\text{total}} = t_1 + t_2$
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8a. $1768.9\,\text{meters}$
8b. $186.2\,\text{m/s}$
- $\approx 1.31\,\text{seconds}$