Question

can you solve this?
6÷2(1 + 2)=
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can you solve this?
9 - 3÷1/3+1=
if the expression above is rewritten in the form a + bi, where a and b are real numbers, what is the value of a? (note: i = √(-1))
a) 2
b) 8/3
c) 3
d) 11/3
if x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?
a) m + 6
b) m + 7
c) 2m+14
d) 3m + 21
f(n)={n/2 if n is even; 3n + 1 if n is odd}

Explanation:

Step1: Solve the parentheses

$1 + 2=3$
The expression becomes $6\div2\times3$.

Step2: Perform division and multiplication from left - to - right

$6\div2 = 3$
Then $3\times3=9$

Answer:

$9$