Question

1. you do: a squirrel is at the top of a 12.7 m tall tree with an acorn in its mouth when it gets startled by a large bird and drops the acorn. how fast should the acorn be moving when it hits the ground?

Explanation:

Step1: Identify the relevant kinematic equation

We use the equation $v^{2}=v_{0}^{2}+2ax$. The initial velocity $v_{0} = 0$ m/s (it is dropped), the acceleration $a = g= 9.8$ m/s² (acceleration due to gravity), and the displacement $x = 12.7$ m.
$v^{2}=0 + 2\times9.8\times12.7$

Step2: Solve for $v$

First, calculate $2\times9.8\times12.7=2\times124.46 = 248.92$. Then, $v=\sqrt{248.92}\approx15.8$ m/s.

Answer:

15.8 m/s