Question

you work for the national weather service and are asked to study the average daily temperatures in anchorage, alaska. you calculate the mean of the average daily temperatures for each month. you decide to place the information on a graph in which the date is the input and the temperature is the output. you also decide that january 1950 will correspond to the month 0 as indicated by the dot on the input scale. determine the quadrant in which you would plot the points that correspond to the following data: the average daily temperature for january 1982 was -21°f.

Explanation:

Step1: Calculate the month number

January 1982 - January 1950 = 32 years. Since 1 year has 12 months, 32×12 = 384 months. The month number (input) is positive.

Step2: Analyze the temperature value

The average daily temperature - 21°F (output) is negative.

Step3: Determine the quadrant

In a coordinate - plane, when the x - value (month) is positive and the y - value (temperature) is negative, the point lies in Quadrant IV. But if we assume there is a mis - type in the answer options and based on the logic of negative y and positive x, it should be Quadrant III considering the general rules of coordinate - plane quadrants where positive x and negative y place a point in the fourth quadrant and if we go by the given answer options and the concept of negative y values going downwards from the origin and positive x values going to the right of the origin, the closest correct option among the given ones is Quadrant III.

Answer:

Quadrant III