Question

5.
\frac{(y^{3}z^{4})(y^{5}z^{-1})}{2} =
\underline{quadquad}

6.
\frac{(3abc^{7})(2a^{4}b^{6})}{6c^{0}} =
\underline{quadquad}

Explanation:

Step1: Multiply like terms (Problem 5)

Multiply $y$-terms and $z$-terms in numerator:
$\frac{y^{2+5}z^{4+(-1)}}{2} = \frac{y^7z^{3}}{2}$

Step2: Multiply coefficients & like terms (Problem 6)

First, multiply coefficients and variables in numerator, use $c^0=1$:
$\frac{(3 \times 2)a^{1+4}b^{1+6}c^{7+0}}{6 \times 1} = \frac{6a^5b^7c^7}{6}$

Step3: Simplify the fraction (Problem 6)

Divide coefficients:
$\frac{6a^5b^7c^7}{6} = a^5b^7c^7$

Answer:

1. $\frac{y^7z^3}{2}$
2. $a^5b^7c^7$