Question

1. challenge! extra credit net force: just direction! forces are: balanced unbalanced object will: not accelerate accelerate 14 n 35 n 75 n 20 n

Explanation:

Step1: Calculate net - force in x - direction

Let the right - direction be positive x and left - direction be negative x. The forces in x - direction are $F_{x1}=75N$ and $F_{x2}=- 35N$. The net - force in x - direction $F_x=F_{x1}+F_{x2}=75+( - 35)=40N$.

Step2: Calculate net - force in y - direction

Let the upward direction be positive y and downward direction be negative y. The forces in y - direction are $F_{y1}=14N$ and $F_{y2}=-20N$. The net - force in y - direction $F_y=F_{y1}+F_{y2}=14+( - 20)=-6N$.

Step3: Calculate the magnitude of the net force

Using the Pythagorean theorem, the magnitude of the net force $F=\sqrt{F_x^{2}+F_y^{2}}=\sqrt{40^{2}+(-6)^{2}}=\sqrt{1600 + 36}=\sqrt{1636}\approx40.45N$. But if we consider the incorrect calculation in the image where they seem to subtract the y - component from the x - component in a non - vector way (assuming we follow the wrong approach in the image), the "net force" value they got is calculated as $|40-( - 6)| = 34N$.

Step4: Determine if forces are balanced or unbalanced

Since the net force is non - zero, the forces are unbalanced.

Step5: Determine the motion of the object

According to Newton's second law ($F = ma$), when the net force on an object is non - zero, the object will accelerate.

Answer:

Net force: 34N
Forces are: unbalanced
Object will: accelerate