Question

1. choose the answer.

a gas at 89 °c occupies a volume of 0.670 l. at what celsius temperature will the volume increase to 1.12 l?
605 °c
332 °c
207 °c

Explanation:

Step1: Convert temp to Kelvin

$T_1 = 89^\circ\text{C} + 273.15 = 362.15\ \text{K}$

Step2: Apply Charles's Law

Charles's Law: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$
Rearrange to solve for $T_2$:
$T_2 = \frac{V_2 \times T_1}{V_1}$
Substitute values: $V_1=0.670\ \text{L}$, $V_2=1.12\ \text{L}$, $T_1=362.15\ \text{K}$
$T_2 = \frac{1.12\ \text{L} \times 362.15\ \text{K}}{0.670\ \text{L}} \approx 605.15\ \text{K}$

Step3: Convert back to Celsius

$T_2 = 605.15\ \text{K} - 273.15 = 332^\circ\text{C}$

Answer:

332 °C