Question

a 10.3 cm b 2.4 cm c 10 cm not drawn to scale which equation can be used to solve for the measure of angle abc? o tan(x) = \frac{2.4}{10} o tan(x) = \frac{10}{2.4} o sin(x) = \frac{10}{10.3} o sin(x) = \frac{10.3}{10}

Explanation:

Step1: Recall trigonometric - ratio definitions

In a right - triangle, $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$ and $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. For angle $ABC$, the opposite side to angle $ABC$ is $AC = 2.4$ cm and the adjacent side is $BC = 10$ cm.

Step2: Determine the tangent of angle $ABC$

Using the tangent formula $\tan(x)=\frac{\text{opposite}}{\text{adjacent}}$, where $x = \angle ABC$, the opposite side to $\angle ABC$ is $AC$ and the adjacent side is $BC$. So, $\tan(x)=\frac{2.4}{10}$.

Answer:

$\tan(x)=\frac{2.4}{10}$