Question

1. examine the code snippet executed in the python shell below and determine what the result will be.

>> spam = 0, 1, 2, 3, 4, 5

>> cheese = spam

>> spam5 = hello!

>> cheese

cheese
0, 1, 2, 3, 4, 5
spam
0, 1, 2, 3, hello!, 5
hello!
0, 1, 2, 3, 4, hello!

1. the join method rearranges items in the list to be in alphanumerical order.

true
false

1. assume m = 1, 2, 3, 4, 5, 6, 7, 8, 9. what does len(m) output?

0
1
2
4
3

Explanation:

Step1: Understand list assignment in Python

In Python, when you do cheese = spam, cheese and spam refer to the same list object in memory.

Step2: Analyze list modification

When spam[5] = 'Hello!' is executed, since cheese and spam are the same list, the change is reflected in cheese too. The original list [0, 1, 2, 3, 4, 5] has its 6 - th element (index 5) changed to 'Hello!', resulting in [0, 1, 2, 3, 4, 'Hello!'].

Step3: Analyze the join method

The join method in Python is used to concatenate elements of an iterable (like a list of strings) into a single string, not to sort elements alphanumerically. So the statement in question 11 is False.

Step4: Analyze the len function on a nested list

The len function on a list returns the number of elements in the list. For m = [[1, 2, 3], [4, 5, 6], [7, 8, 9]], m has 3 elements (the 3 inner lists), so len(m) outputs 3.

Answer:

1. [0, 1, 2, 3, 4, 'Hello!']
2. False
3. 3