Question

1. the mass of the pebble shown below is 2.25 g. what is the density of the pebble?

Explanation:

Step1: Determine the volume of water without pebble

The initial - volume of water in the graduated cylinder is 3.0 mL.

Step2: Determine the volume of water with pebble

The final - volume of water in the graduated cylinder with the pebble is 4.5 mL.

Step3: Calculate the volume of the pebble

The volume of the pebble \(V\) is the difference between the final and initial volumes of water. \(V = 4.5\mathrm{mL}-3.0\mathrm{mL}=1.5\mathrm{mL}\).

Step4: Use the density formula

The density formula is \(
ho=\frac{m}{V}\), where \(m = 2.25\mathrm{g}\) (mass of the pebble) and \(V = 1.5\mathrm{mL}\).
\(
ho=\frac{2.25\mathrm{g}}{1.5\mathrm{mL}} = 1.5\mathrm{g/mL}\)

Answer:

\(1.5\mathrm{g/mL}\)