Question

1. in rabbits, black fur (b) is dominant to white fur (b). a purebred (homozygous) black - furred male is bred with a female that has the recessive white fur.

(there is a punnett square diagram with white fur and black fur as row and column headers respectively, and a bar graph below with phenotype (black fur, white fur) and probability (%) axes)

Explanation:

Step1: Determine Genotypes

The purebred black - furred male is homozygous dominant, so his genotype is \(BB\). The female with recessive white fur is homozygous recessive, so her genotype is \(bb\).

Step2: Set up Punnett Square

When we cross \(BB\) (male) and \(bb\) (female), the male can only produce \(B\) gametes and the female can only produce \(b\) gametes. The Punnett square will have all offspring with genotype \(Bb\).

Step3: Determine Phenotypes

Since \(B\) (black fur) is dominant over \(b\) (white fur), all offspring with genotype \(Bb\) will have black fur. So the probability of black fur is \(\frac{4}{4}=100\%\) and the probability of white fur is \(\frac{0}{4} = 0\%\).

Answer:

Black Fur: \(100\%\)
White Fur: \(0\%\)