QUESTION IMAGE
Question
- rachel tries to keep her lunch choices at or below 750 calories each day. she is at the deli and has chosen oven - roasted chicken wrapped in a spinach tortilla shell. she would like to add 3 slices of bacon, 2 slices of provolone cheese, lettuce, 2 slices of tomato, peppers, guacamole, and mayonnaise. use the table to determine whether rachel will meet her goal of 750 calories or less.
| item | number of calories |
|---|---|
| tomato and herb tortilla | 70 |
| oven roasted chicken | 270 |
| rotisserie style chicken | 310 |
| provolone cheese, per slice | 50 |
| cheddar cheese, per slice | 60 |
| lettuce | 0 |
| tomato, per slice | 5 |
| green peppers | 0 |
| mayonnaise | 100 |
| bacon, per slice | 60 |
| guacamole | 70 |
- no, rachels lunch selection is 800 calories, so it is over her goal of 750 calories.
- no, the lunch will not meet her goal. her selections total over 920 calories.
- rachels lunch selection is 625 calories, so it will meet her goal of 750 calories.
- rachels lunch has exactly 750 calories, so it does meet her goal.
Step1: List out each item and its calories
- Spinach Tortilla: 70
- Oven Roasted Chicken: 270
- Bacon (3 slices): \( 3\times60 = 180 \)
- Provolone Cheese (2 slices): \( 2\times50 = 100 \)
- Lettuce: 0
- Tomato (2 slices): \( 2\times5 = 10 \)
- Green Peppers: 0
- Mayonnaise: 100
- Guacamole: 70
Step2: Sum all the calories
\[
70 + 270 + 180 + 100 + 0 + 10 + 0 + 100 + 70
\]
First, add 70 and 270: \( 70 + 270 = 340 \)
Then add 180: \( 340 + 180 = 520 \)
Then add 100: \( 520 + 100 = 620 \)
Then add 10: \( 620 + 10 = 630 \)
Then add 100: \( 630 + 100 = 730 \)
Then add 70: \( 730 + 70 = 800 \) Wait, no, wait, let's recalculate:
Wait, let's do step by step again:
70 (tortilla) + 270 (chicken) = 340
340 + 180 (bacon) = 520
520 + 100 (provolone) = 620
620 + 0 (lettuce) = 620
620 + 10 (tomato) = 630
630 + 0 (peppers) = 630
630 + 100 (mayonnaise) = 730
730 + 70 (guacamole) = 800
Wait, but the third option says 625, which is wrong. Wait, maybe I missed an item? Wait, the problem says "3 slices of bacon, 2 slices of provolone cheese, lettuce, 2 slices of tomato, peppers, guacamole, and mayonnaise" plus the tortilla and chicken. Wait, did I include all? Let's check again:
Tortilla:70, Chicken:270, Bacon 360=180, Provolone 250=100, Lettuce:0, Tomato 2*5=10, Peppers:0, Mayonnaise:100, Guacamole:70. Sum: 70+270=340; 340+180=520; 520+100=620; 620+0=620; 620+10=630; 630+0=630; 630+100=730; 730+70=800. So total is 800, which is over 750. So the first option says 800, so that's correct. Wait, but when I calculated earlier, I think I made a mistake before. Wait, let's add again:
70 (tortilla) + 270 (chicken) = 340
340 + (3*60=180) = 520
520 + (2*50=100) = 620
620 + 0 (lettuce) = 620
620 + (2*5=10) = 630
630 + 0 (peppers) = 630
630 + 100 (mayonnaise) = 730
730 + 70 (guacamole) = 800. Yes, so total is 800. So the first option is correct: "No, Rachel’s lunch selection is 800 calories, so it is over her goal of 750 calories."
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A. No, Rachel’s lunch selection is 800 calories, so it is over her goal of 750 calories.