Question

1. a man is attempting to pull a wooden box that is currently at rest. the wooden box is resting on a concrete floor. the box has a weight of 112 n. the man pulls with a force of 30 n at an angle of 30 degrees. what is the magnitude of the net force in the horizontal direction? (just put the number do not put the unit, and round to the hundredths position if needed)

Explanation:

Step1: Resolve the pulling - force horizontally

The horizontal component of a force $F$ at an angle $\theta$ is given by $F_x = F\cos\theta$. Here, $F = 30$ N and $\theta=30^{\circ}$.
$F_x = 30\times\cos(30^{\circ})$
Since $\cos(30^{\circ})=\frac{\sqrt{3}}{2}\approx0.866$, then $F_x = 30\times0.866 = 25.98$ N. There is no other horizontal - acting force mentioned in the problem.

Answer:

25.98