Question

1. \\(\frac{9}{10}\\) mi, \\(1\frac{1}{5}\\) mi, \\(1\frac{2}{5}\\) mi (triangle with these side lengths)

Explanation:

Step1: Convert mixed numbers to fractions

$1\frac{1}{5} = \frac{6}{5}$, $1\frac{2}{5} = \frac{7}{5}$

Step2: Unify denominators

$\frac{6}{5} = \frac{12}{10}$, $\frac{7}{5} = \frac{14}{10}$

Step3: Sum all side lengths

$\frac{9}{10} + \frac{12}{10} + \frac{14}{10} = \frac{9+12+14}{10} = \frac{35}{10}$

Step4: Simplify the fraction

$\frac{35}{10} = \frac{7}{2} = 3\frac{1}{2}$

Answer:

$3\frac{1}{2}$ mi