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12x - 10 - 6x a. 6x - 10 b. 2(3x - 5) c. 16x - 8 - 2

Question

12x - 10 - 6x
a. 6x - 10
b. 2(3x - 5)
c. 16x - 8 - 2

Explanation:

Response

Assuming the problem is to simplify \(12x - 10 - 6x\) and check which option (a, b, c) is equivalent, here's the solution:

Step1: Combine like terms

Combine the \(x\)-terms: \(12x - 6x = 6x\). The constant term remains \(-10\). So the expression simplifies to \(6x - 10\).

Step2: Check option b

Expand \(2(3x - 5)\) using the distributive property \(a(b - c)=ab - ac\). Here, \(a = 2\), \(b = 3x\), \(c = 5\). So \(2\times3x - 2\times5 = 6x - 10\), which matches the simplified form.

Step3: Check option c

Simplify \(16x - 8 - 2\). Combine the constant terms: \(-8 - 2=-10\), so it becomes \(16x - 10\), which is not equivalent to \(6x - 10\).

Answer:

a. \(6x - 10\), b. \(2(3x - 5)\) (both are equivalent to \(12x - 10 - 6x\) after simplification/expansion)