Question

1. \\(\

$$\begin{array}{r} 92 \\\\ -47 \\\\ \\hline \\end{array}$$

\\) 14) \\(\

$$\begin{array}{r} 68 \\\\ -29 \\\\ \\hline \\end{array}$$

\\) 15) \\(\

$$\begin{array}{r} 75 \\\\ -18 \\\\ \\hline \\end{array}$$

\\) 16) \\(\

$$\begin{array}{r} 90 \\\\ -34 \\\\ \\hline \\end{array}$$

\\) 17) \\(2 \times 4 = \underline{\quad}\\) 18) \\(2 \times 7\\)

Explanation:

Problem 13: \(

$$\begin{array}{r} 92 \\ - 47 \\ \hline \end{array}$$

\)

Step1: Subtract units place (2 - 7, need to borrow)

Borrow 1 from tens place, so 92 becomes 8 (tens) and 12 (units). Now, \( 12 - 7 = 5 \).

Step2: Subtract tens place (8 - 4)

After borrowing, tens place is 8. \( 8 - 4 = 4 \).

Step1: Subtract units place (8 - 9, need to borrow)

Borrow 1 from tens place, 68 becomes 5 (tens) and 18 (units). \( 18 - 9 = 9 \).

Step2: Subtract tens place (5 - 2)

Tens place is 5 after borrowing. \( 5 - 2 = 3 \).

Step1: Subtract units place (5 - 8, need to borrow)

Borrow 1 from tens place, 75 becomes 6 (tens) and 15 (units). \( 15 - 8 = 7 \).

Step2: Subtract tens place (6 - 1)

Tens place is 6 after borrowing. \( 6 - 1 = 5 \).

Answer:

\( 45 \)

Problem 14: \(

$$\begin{array}{r} 68 \\ - 29 \\ \hline \end{array}$$

\)