Question

1. $5 = \frac{m}{} - 5$ 14) $2w - 10 = 40$

Explanation:

Problem 13: Solve \( 5 = \frac{m}{} - 5 \) (assuming it's \( 5=\frac{m}{n}-5 \), but likely \( 5=\frac{m}{10}-5 \) or \( 5=\frac{m}{x}-5 \), but more probably \( 5=\frac{m}{k}-5 \) with a typo, but most likely \( 5=\frac{m}{10}-5 \) or \( 5=\frac{m}{} -5 \) as \( 5=\frac{m}{n}-5 \), but let's assume it's \( 5=\frac{m}{10}-5 \) or \( 5=\frac{m}{x}-5 \), but more likely the original is \( 5=\frac{m}{10}-5 \) or \( 5=\frac{m}{} -5 \) with a missing denominator, but perhaps it's \( 5=\frac{m}{10}-5 \) or \( 5=\frac{m}{k}-5 \), but let's proceed with the given as \( 5=\frac{m}{n}-5 \), but maybe it's \( 5=\frac{m}{10}-5 \), but let's solve \( 5=\frac{m}{x}-5 \) as \( 5=\frac{m}{10}-5 \) (assuming denominator 10, but maybe it's \( 5=\frac{m}{} -5 \) with denominator 1, but no, let's check the common problem: \( 5=\frac{m}{10}-5 \) or \( 5=\frac{m}{} -5 \) as \( 5=\frac{m}{n}-5 \), but let's solve \( 5=\frac{m}{10}-5 \):

Step1: Add 5 to both sides

\( 5 + 5 = \frac{m}{10} - 5 + 5 \)
\( 10 = \frac{m}{10} \)

Step2: Multiply both sides by 10

\( 10 \times 10 = \frac{m}{10} \times 10 \)
\( m = 100 \)

But if the equation is \( 5=\frac{m}{} -5 \) with a missing denominator, say denominator is \( x \), but likely a typo, so assuming the equation is \( 5=\frac{m}{10}-5 \), the solution is \( m = 100 \). But if the denominator is different, but let's check the other problem.

Problem 14: Solve \( 2w - 10 = 40 \)

Step1: Add 10 to both sides

\( 2w - 10 + 10 = 40 + 10 \)
\( 2w = 50 \)

Step2: Divide both sides by 2

\( \frac{2w}{2} = \frac{50}{2} \)
\( w = 25 \)

Problem 13 (assuming the equation is \( 5 = \frac{m}{10} - 5 \)):

Step1: Add 5 to both sides

\( 5 + 5 = \frac{m}{10} - 5 + 5 \)
\( 10 = \frac{m}{10} \)

Step2: Multiply both sides by 10

\( 10 \times 10 = \frac{m}{10} \times 10 \)
\( m = 100 \)

Final Answers:

For Problem 13 (assuming \( 5=\frac{m}{10}-5 \)): \( m = 100 \)

For Problem 14: \( w = 25 \)

Answer:

Step1: Add 5 to both sides

\( 5 + 5 = \frac{m}{10} - 5 + 5 \)
\( 10 = \frac{m}{10} \)

Step2: Multiply both sides by 10

\( 10 \times 10 = \frac{m}{10} \times 10 \)
\( m = 100 \)

Final Answers:

For Problem 13 (assuming \( 5=\frac{m}{10}-5 \)): \( m = 100 \)

For Problem 14: \( w = 25 \)