Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

13. use the graph on the side to answer questions a - f. a. what is the…

Question

  1. use the graph on the side to answer questions a - f.

a. what is the displacement of the object at 8 hours?
b. what is the displacement of the object at 18 hours?
c. is the object accelerating from a to b or is it constant velocity? how can you tell?
d. what is the velocity of the object from c to d?
e. what is the velocity of the object from d to e?

  1. use the graph on the side to answer questions a - e

a. what is the velocity at 10 seconds?
b. what is the velocity at 5 seconds?
c. what is the acceleration between 8 and 10 seconds?
d. what is the acceleration between 10 and 14 seconds?
e. what is the displacement between 0 and 14 seconds?

Explanation:

Step1: For question 13a

Read the displacement - time graph at \(t = 8\) hours.

Step2: For question 13b

Read the displacement - time graph at \(t=18\) hours.

Step3: For question 13c

In a displacement - time graph, constant velocity means a straight - line segment and acceleration means a curved or non - straight line segment. Analyze the segment from A to B.

Step4: For question 13d

Velocity in a displacement - time graph is the slope of the line segment. Calculate the slope for the segment from C to D using the formula \(v=\frac{\Delta d}{\Delta t}\), where \(\Delta d\) is the change in displacement and \(\Delta t\) is the change in time.

Step5: For question 13e

Calculate the slope of the line segment from D to E using \(v = \frac{\Delta d}{\Delta t}\).

Step6: For question 14a

If it is a velocity - time graph, read the value of velocity at \(t = 10\) seconds.

Step7: For question 14b

Read the value of velocity at \(t=5\) seconds from the velocity - time graph.

Step8: For question 14c

Acceleration \(a=\frac{\Delta v}{\Delta t}\), calculate the change in velocity \(\Delta v\) and change in time \(\Delta t\) between 8 and 10 seconds.

Step9: For question 14d

Calculate \(a=\frac{\Delta v}{\Delta t}\) for the time interval between 10 and 14 seconds.

Step10: For question 14e

If it is a velocity - time graph, the displacement is the area under the curve between 0 and 14 seconds. Calculate the area under the curve.

Since the actual graph values are not provided, we cannot give numerical answers. But the general methods for answering each part are as above.

Answer:

13a. Cannot be determined without graph values.
13b. Cannot be determined without graph values.
13c. Analyze the straight - line nature of segment A - B on displacement - time graph to determine.
13d. Cannot be determined without graph values (calculate slope of C - D).
13e. Cannot be determined without graph values (calculate slope of D - E).
14a. Cannot be determined without graph values.
14b. Cannot be determined without graph values.
14c. Cannot be determined without graph values (use \(a=\frac{\Delta v}{\Delta t}\)).
14d. Cannot be determined without graph values (use \(a=\frac{\Delta v}{\Delta t}\)).
14e. Cannot be determined without graph values (calculate area under curve).