Question

1. if bc = 5 and cd = 26, find ac.

√31
130
31
√130

Explanation:

Step1: Apply geometric - mean theorem

In right - triangle $ABD$ with altitude $AC$ to the hypotenuse $BD$, we have $AC^{2}=BC\times CD$.

Step2: Substitute given values

Given $BC = 5$ and $CD=26$, then $AC^{2}=5\times26$.

Step3: Calculate $AC$

$AC^{2}=130$, so $AC = \sqrt{130}$.

Answer:

$\sqrt{130}$