Question

1. find the height of the trapezoid.

6 m
area = 40 m²
10 m
□ m
grade 6: mrl cc>chapter 7>practice test> question #11

Explanation:

Step1: Recall trapezoid area formula

The area of a trapezoid is given by $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1$ and $b_2$ are the lengths of the two parallel sides, and $h$ is the height.

Step2: Substitute known values

We know $A = 40$, $b_1 = 6$, $b_2 = 10$. Plug these into the formula:
$40 = \frac{1}{2}(6 + 10)h$

Step3: Simplify the sum inside parentheses

Calculate $6 + 10 = 16$, so:
$40 = \frac{1}{2}(16)h$

Step4: Simplify the right-hand side

$\frac{1}{2}(16) = 8$, so:
$40 = 8h$

Step5: Solve for $h$

Divide both sides by 8:
$h = \frac{40}{8}$

Answer:

$5$ m