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Question
- the area of a rectangular pool is 10 more than three times its width. choose the correct set - up to represent an equation for the area of this garden. a. a = 10w + 3 b. a = 3w + 10 c. a = 10w - 3 d. a = 3w - 10
- the area of a rectangular garden is 12 less than 4 times its perimeter. choose the correct set - up to represent an equation for the area of the pool. a. a = 12 - 4p b. a = 12p - 4 c. a = 4p - 12 d. a = 4 - 12p
- the length of a rectangle is 10 inches more than twice a number. write the equation for the length of the rectangle.
- the width is 5 inches less than a number. write the equation for the width of the rectangle.
- the length of a rectangle is 8 inches less than three times a number. write the equation for the length of the rectangle.
- the width is 4 inches more than half of a number. write the equation for the width of the rectangle.
- the length of a square is 4x + 5. the width of the square is 2x + 15. if the length and width are the same, find the value of x. what is the side length of the square?
side length =
x =
Step1: Analyze problem 15
Let width be $w$. Area $A$ is 10 more than three - times width, so $A = 3w+10$.
Step2: Analyze problem 16
Let perimeter be $p$. Area $A$ is 12 less than 4 times perimeter, so $A = 4p - 12$.
Step3: Analyze problem 17
Let the number be $n$. Length $l$ is 10 inches more than twice the number, so $l=2n + 10$.
Step4: Analyze problem 18
Let the number be $n$. Width $w$ is 5 inches less than the number, so $w=n - 5$.
Step5: Analyze problem 19
Let the number be $n$. Length $l$ is 8 inches less than three times the number, so $l = 3n-8$.
Step6: Analyze problem 20
Let the number be $n$. Width $w$ is 4 inches more than half of the number, so $w=\frac{n}{2}+4$.
Step7: Analyze problem 21
For a square, length = width. So $4x + 5=2x+15$.
Subtract $2x$ from both sides: $4x-2x + 5=2x-2x + 15$, which simplifies to $2x+5 = 15$.
Subtract 5 from both sides: $2x+5 - 5=15 - 5$, so $2x=10$.
Divide both sides by 2: $\frac{2x}{2}=\frac{10}{2}$, then $x = 5$.
The side - length of the square is $4x + 5=4\times5+5=25$ (or $2x + 15=2\times5+15=25$).
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- B. $A = 3w + 10$
- C. $A = 4p - 12$
- $l=2n + 10$
- $w=n - 5$
- $l = 3n-8$
- $w=\frac{n}{2}+4$
- $x = 5$, Side Length = 25