Question

15
factor by gcf
$abcd+abc$
$a(bcd+bc)$ $ab(cd+c)$
$abc(d-1)$ $abc(d+1)$

Explanation:

Step1: Identify the GCF

The greatest common factor of $abcd$ and $abc$ is $abc$.

Step2: Factor out the GCF

Divide each term by $abc$ and rewrite the expression:
$abcd + abc = abc(d + 1)$

Answer:

abc(d+1)