Question

1. find ce. find the length indicated. b 3x + 47 c d 10 e 27 + x x + 26

Explanation:

Step1: Set up an equation based on segment - addition

Since $BC + CD+DE=BE$, we have $(3x + 47)+(27 + x)+(x + 26)=10$.

Step2: Combine like - terms

Combining the $x$ terms and the constant terms on the left - hand side gives $3x+x+x+47 + 27+26 = 10$, which simplifies to $5x+100 = 10$.

Step3: Solve for $x$

Subtract 100 from both sides: $5x=10 - 100=-90$. Then divide both sides by 5: $x=\frac{-90}{5}=-18$.

Step4: Find the length of $CE$

$CE=CD + DE=(27 + x)+(x + 26)$. Substitute $x = - 18$ into the expression for $CE$.
$CE=(27-18)+(-18 + 26)=9 + 8 = 17$.

Answer:

17